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Founder
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Question Stats:
80% (01:24) correct
19% (00:55) wrong based on 56 sessions
Quantity A |
Quantity B |
\(\frac{6^85^34^2}{3^68^2}\) |
\(\frac{6^95^34^3}{3^82^8}\) |
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
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Re: 6^85^34^2/3^68^2 [#permalink]
 21 Sep 2017, 09:01
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If we compare the two quantities we see we can simplify them until we get 1/64 and 1/96 so that A is larger!
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Re: 6^85^34^2/3^68^2 [#permalink]
02 Apr 2018, 12:21
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Answer: A
We just compare the two values and try to simplify them.
A ------------------------------------------------B
6^8 * 5^3 * 4^2 / 3^6 * 8^2 ------------------ 6^9 * 5^3 * 4^3 / 3^8 * 2^8
Multiply them by the minimum power of each element in the two values. 3^6 /6^8 * 5^3 * 4^2
The result will be a simple form
1/ 8^2 -------------------------------------------6 * 4 /3^2 * 2^8
We convert 8^2 and 2^ 8 to one single form. 8^2 = (2^3)^2 = 2^2*3 = 2^ 6
1/ 2^6--------------------------------------------6* 4 / 2^ 8 *3^2
Multiply both is 2^6:
1-------------------------------------------------6 * 4 / 2^2 * 3^2 = 2/3
So B is bigger than A.[/b]
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Re: 6^85^34^2/3^68^2 [#permalink]
04 Apr 2018, 07:25
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Instead of simplifying the whole terms, we can remove the terms which are common in both of the quantities and then compare the remaining parts
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Re: 6^85^34^2/3^68^2 [#permalink]
05 Jul 2019, 02:03
Let us remove the terms that are common on both sides
A: 1/8^2
B: (6*4)/(3^2 2^8 )
Lets rewrite A and B in terms of 2 and 3
A: 1/2^6
B: (2*3*2^2)/(3^2 2^8 )
Lets simplify the QTY B
A: 1/2^6
B: 2/3
Hence B is bigger.
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Re: 6^85^34^2/3^68^2
[#permalink]
05 Jul 2019, 02:03
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