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Founder  Joined: 18 Apr 2015
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Expert's post 00:00

Question Stats: 84% (00:19) correct 15% (00:16) wrong based on 210 sessions

 Quantity A Quantity B 5(r + t) 5r + t

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Expert's post
Carcass wrote:

 Quantity A Quantity B 5(r + t) 5r + t

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Let's use the strategy of matching operations

Given:
Quantity A: 5(r + t)
Quantity B: 5r + t

Expand:
Quantity A: 5r + 5t
Quantity B: 5r + t

Subtract 5r from both quantities to get:
Quantity A: 5t
Quantity B: t

Subtract t from both quantities to get:
Quantity A: 4t
Quantity B: 0

Divide both quantities by 4 to get:
Quantity A: t
Quantity B: 0

Since there's no way to tell whether t is less than, equal to, or greater than 0, the correct answer is D

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Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course. Intern Joined: 08 Mar 2018
Posts: 11
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Kudos [?]: 10 , given: 10

I believe the question is copied wrong. Quantity B should be 5r + t not 5r+5
GreenlightTestPrep wrote:
Carcass wrote:

 Quantity A Quantity B 5(r + t) 5r + t

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Let's use the strategy of matching operations

Given:
Quantity A: 5(r + t)
Quantity B: 5r + 5

Expand:
Quantity A: 5r + 5t
Quantity B: 5r + 5

Subtract 5r from both quantities to get:
Quantity A: 5t
Quantity B: 5

Divide both quantities by 5 to get:
Quantity A: t
Quantity B: 1

Since there's no way to tell whether t is less than, equal to, or greater than 1, the correct answer is D

RELATED VIDEO Intern Joined: 08 Mar 2018
Posts: 11
Followers: 0

Kudos [?]: 10  , given: 10

2
KUDOS
5(r+t) 5r+t
5r+5t 5r +t
5t t (subtract 5r)
5 1 (divide by t)
5>1
GRE Instructor Joined: 10 Apr 2015
Posts: 3840
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Kudos [?]: 4506 , given: 69

Expert's post
kkaur423 wrote:
I believe the question is copied wrong. Quantity B should be 5r + t not 5r+5

You're absolutely right.
I have edited my response accordingly.

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course.  GRE Instructor Joined: 10 Apr 2015
Posts: 3840
Followers: 149

Kudos [?]: 4506  , given: 69

2
KUDOS
Expert's post
kkaur423 wrote:
5(r+t) 5r+t
5r+5t 5r +t
5t t (subtract 5r)
5 1 (divide by t)
5>1

There's a slight error in your solution.
When using matching operations, we must be sure to avoid multiplying or dividing a quantity by a negative number.
In your solution, you divided both quantities by t. However, since we don't know whether t is positive or negative, we must avoid dividing the quantities by t.

Let's take it from where you got to:
Quantity A: 5t
Quantity B: t

Notice that, if t = 0, then the two quantities are equal.
If t = 1, then Quantity A is greater
If t = -1, then Quantity B is greater
So, the correct answer must be D.

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course. Intern Joined: 15 May 2018
Posts: 38
Followers: 0

Kudos [?]: 6 , given: 1

Carcass wrote:

 Quantity A Quantity B 5(r + t) 5r + t

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Intern  Joined: 04 May 2017
Posts: 36
Followers: 0

Kudos [?]: 29 , given: 6

Observe that 5r is the same, but we don't know the sign of t -> D
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Do not pray for an easy life, pray for the strength to endure a difficult one - Bruce Lee Intern Joined: 09 Jul 2018
Posts: 10
Followers: 1

Kudos [?]: 16  , given: 0

1
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Carcass wrote:
 Quantity A Quantity B 5(r + t) 5r + t

Case 1: t=0
In this case, quantity A $$= 5(r+0) = 5r$$ and quantity B $$= 5r+0 = 5r$$, so the two quantities are equal.
Eliminate A and B.

Case 2: t=1
In this case, quantity A $$= 5(r+1) = 5r + 5$$ and quantity B $$= 5r + 1$$, so the two quantities are NOT equal.
Eliminate C.

[Reveal] Spoiler:
D

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Manager Joined: 19 Mar 2018
Posts: 61
Followers: 1

Kudos [?]: 25 , given: 34

A B
5r + 5t 5r + t
5r removed from both sides
5t> t so A

However I have a question --> what if T is ZERO?
then 0 = 0 and answer would be D
Founder  Joined: 18 Apr 2015
Posts: 13406
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Kudos [?]: 3406 , given: 12285

Expert's post
See the explanation atop your question provided by GMATGuruNY.

If t=0 the answer is C.

If t=1 the two quantities are different.

D is the right answer, therefore.

See for a proper strategy https://greprepclub.com/forum/quantitat ... 10440.html

Regards
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Intern Joined: 27 Nov 2014
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Kudos [?]: 5 , given: 0

I picked D Re: 5(r + t)   [#permalink] 29 Sep 2018, 11:04
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