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3x + 5y + 2z = 20 6x + 4z = 10

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3x + 5y + 2z = 20 6x + 4z = 10 [#permalink] New post 17 Sep 2017, 11:55
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Question Stats:

70% (00:29) correct 29% (00:14) wrong based on 17 sessions


3x + 5y + 2z = 20
6x + 4z = 10

Quantity A
Quantity B
y
2


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: 3x + 5y + 2z = 20 6x + 4z = 10 [#permalink] New post 17 Sep 2017, 14:17
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Expert's post
Carcass wrote:
3x + 5y + 2z = 20
6x + 4z = 10

Quantity A
Quantity B
y
2


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Given:
3x + 5y + 2z = 20
6x + 4z = 10

Take top equation and multiply both sides by 2 to get the following equivalent equation:
6x + 10y + 4z = 40
6x + 4z = 10

Subtract the bottom equation from the top equation to get: 10y = 30
Solve: y = 3

So, we get:
Quantity A: 3
Quantity B: 2

Answer:
[Reveal] Spoiler:
A


Cheers,
Brent
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Re: 3x + 5y + 2z = 20 6x + 4z = 10   [#permalink] 17 Sep 2017, 14:17
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