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(3x – 4y)(3x + 4y) = 2
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Carcass
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(3x – 4y)(3x + 4y) = 2 [#permalink] New post  22 May 2017, 01:49
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\((3x – 4y)(3x + 4y) = 2\)

Quantity A
Quantity B
\(9x^2 – 16y^2\)
\(4\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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GreenlightTestPrep
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Re: (3x – 4y)(3x + 4y) = 2 [#permalink] New post  22 May 2017, 07:04
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Carcass wrote:


(3x – 4y)(3x + 4y) = 2

Quantity A
Quantity B
9x² – 16y²
4


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Given: (3x – 4y)(3x + 4y) = 2
Expand and simplify left side to get: 9x² – 16y² = 2

So, we have:
Quantity A: 2
Quantity B: 4

Answer: B
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mrr0821
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Re: (3x – 4y)(3x + 4y) = 2 [#permalink] New post  29 Sep 2018, 11:48
Easy one. B
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akingba
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Re: (3x – 4y)(3x + 4y) = 2 [#permalink] New post  05 Feb 2019, 05:37
A: 9x² – 16y² = 2
B: 4

Answer is B
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Re: (3x – 4y)(3x + 4y) = 2 [#permalink] New post  30 Sep 2019, 03:11
1
This question tests whether you know the "difference of squares" formula: a^2 - b^2 = (a+b)*(a-b)
No real traps in this question.
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