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# 32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
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Kudos [?]: 1973 [0], given: 397

32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28 [#permalink]  19 May 2018, 12:26
Expert's post
00:00

Question Stats:

100% (00:11) correct 0% (00:00) wrong based on 9 sessions
$$\frac{32}{4 + 6 × 2}=$$

(A) 8/5
(B) 16/5
(C) 2
(D) 20
(E) 28
[Reveal] Spoiler: OA

_________________

Sandy
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Kudos [?]: 1986 [0], given: 20

Re: 32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28 [#permalink]  13 May 2019, 04:54
Expert's post
sandy wrote:
$$\frac{32}{4 + 6 × 2}=$$

(A) 8/5
(B) 16/5
(C) 2
(D) 20
(E) 28

This is all about the order of operations

PEMDAS (aka BEDMAS) tells We must evaluate the stuff in the brackets first: $$4 + 6 × 2$$
We must also complete all multiplication before addition.
So, $$4 + 6 × 2 = 4 + 12 = 16$$

So, $$\frac{32}{4 + 6 × 2}=\frac{32}{16}=2$$

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com

Re: 32/(4 + 6 × 2) = (A) 8/5 (B) 16/5 (C) 2 (D) 20 (E) 28   [#permalink] 13 May 2019, 04:54
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