The first equation can be solved algebraically,
\(3(x – 7) \geq 9\)

or\(x - 7 \geq 3\)

or \(x \geq 10\)

For 2nd equation:

\(0.25y – 3 \leq 1\)

or \(0.25y \leq 4\)

or \(y\leq 16\)

So we cannot reach to a definite solution for this because x can be of any value from 10 and y can be any value less than or equal to 16

So option is D
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