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2x + 1 > 3x + 2 and 5x + 2 > 4x
[#permalink]
17 Sep 2018, 20:29
17 Sep 2018, 20:29
Expert Reply
00:00
Question Stats:
82% (00:48) correct
17% (01:04) wrong based on 58 sessions
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\(2x + 1 > 3x\) + 2 and \(5x + 2 > 4x\)
Quantity A |
Quantity B |
x |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: 2x + 1 > 3x + 2 and 5x + 2 > 4x
[#permalink]
17 Sep 2018, 22:15
17 Sep 2018, 22:15
1
Carcass wrote:
\(2x + 1 > 3x\) + 2 and \(5x + 2 > 4x\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(2x + 1 > 3x + 2\)
or \(x < -1\)
\(5x + 2 > 4x\)
or \(x > -2\)
Therefore \(-2 < x < -1\)
So, QTY A < QTY B
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Re: 2x + 1 > 3x + 2 and 5x + 2 > 4x
[#permalink]
20 Sep 2018, 12:52
20 Sep 2018, 12:52
1
Expert Reply
Carcass wrote:
\(2x + 1 > 3x\) + 2 and \(5x + 2 > 4x\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Turns out that we can solve this with only the first inequality: 2x + 1 > 3x + 2
Take: 2x + 1 > 3x + 2
Subtract 2x from both sides: 1 > x + 2
Subtract 2 from both sides: -1 > x
Since x is less than -1, we can be certain that x is less than 1
Answer: B
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