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2ab5 is a four-digit number divisible by 25. If the number f

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2ab5 is a four-digit number divisible by 25. If the number f [#permalink] New post 14 Apr 2018, 02:40
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Question Stats:

76% (01:20) correct 23% (01:09) wrong based on 13 sessions
2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =

(A) 10
(B) 25
(C) 52
(D) 65
(E) 75
[Reveal] Spoiler: OA

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Re: 2ab5 is a four-digit number divisible by 25. If the number f [#permalink] New post 20 Apr 2018, 03:46
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Since it is given that ab is divisible by \(13\) we should first check ans choices to eliminate options that are not divisible by \(13\):

option a: \(10\) is below \(13\)so it is not divisible by \(13\)
option b: \(25\) is one less than \(26\) so it is also not divisible by \(13\)
option c: \(52\) is divisible by \(13\) so let us see if the total number replaced by \(52\) for the position ab is divisible by \(25\)
\(\frac{2525}{25}= 101\)
option C
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Re: 2ab5 is a four-digit number divisible by 25. If the number f [#permalink] New post 17 Jul 2018, 12:26
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Carcass wrote:
2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =

(A) 10
(B) 25
(C) 52
(D) 65
(E) 75



Note :

ab is a multiple of 13. So, we can eliminate Option A, B, and E.

Option C:

2525 / 25.........clearly divisible. So, ab must be 52.

The best answer is C.
Re: 2ab5 is a four-digit number divisible by 25. If the number f   [#permalink] 17 Jul 2018, 12:26
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2ab5 is a four-digit number divisible by 25. If the number f

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