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1/2(x+z)

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1/2(x+z) [#permalink] New post 04 Feb 2018, 15:11
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Attachment:
triangle.jpg
triangle.jpg [ 12.73 KiB | Viewed 1119 times ]


Quantity A
Quantity B
\(x\)
\(\frac{1}{2}(x+z)\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: 1/2(x+z) [#permalink] New post 04 Feb 2018, 20:13
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C

look at the corresponding angles to each side and you'll notice that z=x. Equilateral triangle.

therefore x+z=2x

2x/2=x
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Re: 1/2(x+z) [#permalink] New post 05 Feb 2018, 02:49
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Carcass wrote:


Attachment:
The attachment triangle.jpg is no longer available


Quantity A
Quantity B
\(x\)
\(\frac{1}{2}(x+z)\)





Here given the two sides denoted as =x and two angles are denoted as = \(a^0\)

So the third angle will also be \(a^0\) (as shown in the figure), because the angles of equal sides is also equal.

So the triangle represent an equilateral triangle.

Hence QTY A = QTY B. Hence option C
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Re: 1/2(x+z) [#permalink] New post 07 Feb 2018, 02:05
Answer: C
Re: 1/2(x+z)   [#permalink] 07 Feb 2018, 02:05
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