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2^30-2^29/2

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2^30-2^29/2 [#permalink] New post 16 May 2018, 09:09
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Question Stats:

87% (00:21) correct 12% (00:28) wrong based on 16 sessions
Quantity A
Quantity B
\(\frac{2^{30} - 2^{29}}{2}\)
\(2^{28}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: 2^30-2^29/2 [#permalink] New post 16 May 2018, 09:22
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In A, taking 2^29 common and solving would give same value as B

Hence they are both equal
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Re: 2^30-2^29/2 [#permalink] New post 16 May 2018, 23:43
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simplify qty A:
Take \(2^{29}\) common

\(\frac{2^{29}(2-1)}{2}\) this reduces to

\(\frac{2^{29}}{2^1}\)

when \(2^1\) goes into the numerator the expression further simplifies to:
\(2^{29} * 2^{-1} = 2^{28}\)

option C
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Last edited by Carcass on 17 May 2018, 04:09, edited 1 time in total.
Edited by Carcass
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Re: 2^30-2^29/2 [#permalink] New post 17 May 2018, 04:09
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Thank you. Formatted in a better manner.

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Re: 2^30-2^29/2   [#permalink] 17 May 2018, 04:09
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