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2>3a>0

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2>3a>0 [#permalink] New post 04 Jul 2019, 07:11
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Question Stats:

89% (00:27) correct 10% (00:14) wrong based on 48 sessions
\(2>3a>0\)

Quantity A
Quantity B
\(a\)
\(a^2\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: 2>3a>0 [#permalink] New post 04 Jul 2019, 09:57
Expert's post
Carcass wrote:
\(2>3a>0\)

Quantity A
Quantity B
\(a\)
\(a^2\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


We can solve this question using matching operations

Given:
Quantity A: \(a\)
Quantity B: \(a^2\)

Since we're told \(a\) is POSITIVE, we can safely divide both quantities by \(a\) to get:
Quantity A: \(1\)
Quantity B: \(a\)

Now take the given information: \(2>3a>0\)

Divide all parts by 3 to get: \(\frac{2}{3}>a>0\)

Since \(a<\frac{2}{3}\), it must be the case that \(a<1\)

Answer: A


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Re: 2>3a>0 [#permalink] New post 30 Jun 2020, 02:56
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Here is my solution.
Notice that 2>3a>0, a here must be fraction.
QA a
QB a^2
when squaring a fraction it gets smaller, answer must be A.
Re: 2>3a>0   [#permalink] 30 Jun 2020, 02:56
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