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Founder  Joined: 18 Apr 2015
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2^3 * 17 * 5^2 [#permalink]
Expert's post 00:00

Question Stats: 100% (00:56) correct 0% (00:00) wrong based on 30 sessions
 Quantity A Quantity B $$\frac{2^3 * 17 * 5^2}{60}$$ $$\frac{255}{2}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

_________________ VP Joined: 20 Apr 2016
Posts: 1302
WE: Engineering (Energy and Utilities)
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Re: 2^3 * 17 * 5^2 [#permalink]
1
KUDOS
Carcass wrote:
 Quantity A Quantity B $$\frac{2^3 * 17 * 5^2}{60}$$ $$\frac{255}{2}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

QTY A = $$\frac{2^3 * 17 * 5^2}{60} = \frac{8 * 17 * 25}{60} = \frac{170}{3}$$

As we compare we find the numerator of QTY A is less than the numerator of QTY B and

the denominator of QTY A is greater than the denominator of QTY B

Hence QTY A < QTY B

Option B
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Re: 2^3 * 17 * 5^2 [#permalink]
Expert's post
Carcass wrote:
 Quantity A Quantity B $$\frac{2^3 * 17 * 5^2}{60}$$ $$\frac{255}{2}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Let's do a little prime factorization

Given:
Quantity A: $$\frac{2^3 * 17 * 5^2}{60}=\frac{(2)(2)(2)(17)(5)(5)}{(2)(2)(3)(5)}$$

Quantity B: $$\frac{255}{2}=\frac{(3)(5)(17)}{2}$$

Simplify Quantity A to get:
Quantity A: $$\frac{(2)(17)(5)}{(3)}$$

Quantity B: $$\frac{(3)(5)(17)}{2}$$

Divide both quantities by 5 and by 17 to get:
Quantity A: $$\frac{2}{3}$$

Quantity B: $$\frac{3}{2}$$

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com  Re: 2^3 * 17 * 5^2   [#permalink] 07 Jun 2019, 07:54
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