soumya1989 wrote:

x = 1/3 + 1/9 + 1/27 + 1/37

Column A | Column B |

101st digit after the decimal point in the decimal representation of x | 5 |

A bit hard one. Truth be told chances of getting a question like this in actual GRE is quite slim. Still good to practise these.

Kudos to the answer with the best explanation.

LCM of 27 & 37 is 999. So whatever goes to numerator, will repeat itself in the decimal reprsentation. In this case it is 508.

Now, 101 leaves a remainder of 2 when it is divided by the cyclicity period of the representation. Here, the cyclicity period is 3.

Therefore the 2nd digit of 508 will be the 101th number.

Ans: B