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# -101^102

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Founder
Joined: 18 Apr 2015
Posts: 7418
Followers: 125

Kudos [?]: 1454 [0], given: 6625

-101^102 [#permalink]  20 Oct 2017, 02:42
Expert's post
00:00

Question Stats:

100% (00:08) correct 0% (00:00) wrong based on 42 sessions

 Quantity A Quantity B $$(-101)^{102}$$ $$(-102)^{101}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
Director
Joined: 03 Sep 2017
Posts: 520
Followers: 1

Kudos [?]: 363 [2] , given: 66

Re: -101^102 [#permalink]  20 Oct 2017, 04:58
2
KUDOS
Without computations, quantity A is elevated to an even exponent, thus the result is positive. Quantity B, instead, is elevated to an odd exponent, thus the result is still negative.

Quantity A is greater!
GRE Instructor
Joined: 10 Apr 2015
Posts: 2176
Followers: 65

Kudos [?]: 1992 [0], given: 20

Re: -101^102 [#permalink]  22 Apr 2019, 17:52
Expert's post
Carcass wrote:

 Quantity A Quantity B $$(-101)^{102}$$ $$(-102)^{101}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Rule #1: ODD exponents preserve the sign of the base.
So, (NEGATIVE)^(ODD integer) = NEGATIVE
and (POSITIVE)^(ODD integer) = POSITIVE

Rule #1: An EVEN exponent always yields a positive result (unless the base = 0)
So, (NEGATIVE)^(EVEN integer) = POSITIVE
and (POSITIVE)^(EVEN integer) = POSITIVE

By rule #1, Quantity A is POSITIVE
By rule #2, Quantity B is NEGATIVE

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com

Re: -101^102   [#permalink] 22 Apr 2019, 17:52
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