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# 1 > x > y > 0

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1 > x > y > 0 [#permalink]  08 Jan 2018, 14:16
Expert's post
00:00

Question Stats:

86% (00:34) correct 13% (00:51) wrong based on 15 sessions

$$1 > x > y > 0$$

 Quantity A Quantity B $$x^2$$ $$y^2$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudo for the right answer and explanation.
[Reveal] Spoiler: OA

_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 1177
Followers: 44

Kudos [?]: 1053 [1] , given: 6

Re: 1 > x > y > 0 [#permalink]  09 Jan 2018, 12:09
1
KUDOS
Expert's post
Carcass wrote:

$$1 > x > y > 0$$

 Quantity A Quantity B $$x^2$$ $$y^2$$

If 0 < y < x, then y² < x²

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com

GRE Instructor
Joined: 10 Apr 2015
Posts: 1177
Followers: 44

Kudos [?]: 1053 [0], given: 6

Re: 1 > x > y > 0 [#permalink]  09 Jan 2018, 12:14
Expert's post
Carcass wrote:

$$1 > x > y > 0$$

 Quantity A Quantity B $$x^2$$ $$y^2$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudo for the right answer and explanation.

Here's another approach:

Given:
Quantity A: x²
Quantity B: y²

Subtract y² from both quantities:
Quantity A: x² - y²
Quantity B: 0

Factor quantity B:
Quantity A: (x + y)(x - y)
Quantity B: 0

Since 0 < y < x, we know that x + y is POSITIVE, and we know that x - y is POSITIVE

So, we get:
Quantity A: (POSITIVE)(POSITIVE)
Quantity B: 0

Since the Quantity A must evaluate to be SOME POSITIVE value, Quantity A must be greater.

RELATED VIDEO FROM OUR COURSE

_________________

Brent Hanneson – Creator of greenlighttestprep.com

Re: 1 > x > y > 0   [#permalink] 09 Jan 2018, 12:14
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