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1/5 of all the cars on a certain auto lot are red, and

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1/5 of all the cars on a certain auto lot are red, and [#permalink] New post 11 Jul 2019, 02:05
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\(\frac{1}{5}\) of all the cars on a certain auto lot are red, and \(\frac{2}{3}\) of all the red cars are convertibles. What fraction of all the cars are NOT red convertibles?


Give your answer as a fraction.

[Reveal] Spoiler: OA
\(\frac{13}{15}\)

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Re: 1/5 of all the cars on a certain auto lot are red, and [#permalink] New post 11 Jul 2019, 08:42
We know that 1/5 of all cars on a certain lot are red.
So, red cars, r = 1/5
and we know that 2/3 of red cars are red convertibles.
So, red convertibles, c = 2/3 (r) = 2/3 * 1/5 = 2/15. -> total red convertibles.
Then, a fraction of all the cars which are NOT red convertibles = 1 -2/15 = 13/15.
Re: 1/5 of all the cars on a certain auto lot are red, and   [#permalink] 11 Jul 2019, 08:42
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1/5 of all the cars on a certain auto lot are red, and

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