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1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with

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1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with [#permalink] New post 03 Apr 2018, 18:51
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1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with 1 and repeats in the pattern 1, 2, -3, -4 indefinitely

Quantity A
Quantity B
The sum of the 49th and 51st terms
The sum of the 50th and 52nd terms


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA
Director
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Re: 1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with [#permalink] New post 05 Apr 2018, 02:50
The pattern repeats in a finite order. The \(1st, 5th, 9th\) term and so on are \(1\)
Similarly, \(2nd, 6th, 10th\) term and so on are \(2\)
\(-3\) and \(-4\) also repeat in a difference of 4 numbers.

Since all the numbers repeat in a difference of \(4\) we can find the position of given term by finding the remainder when divided by \(4\)

For qty A
when \(49\) is divided by \(4\) remainder is \(1\) so the \(49th\) term has value of \(1\) from the \(1st\) number in the sequence
similarly when \(51st\) term is divided by \(4\) the remainder is \(3\) so the the \(51st\) term has the value \(-3\) which is the third number in the sequence
sum of \(-3\) and \(1 = -2\)

For qty B
when \(50\) is divided by \(4\) remainder is \(2\) so the \(50\)th term has value of \(2\) from the 2nd number in the sequence
when \(52\) is divided by\(4\) remainder is \(0\) so the \(52\)nd term has value of \(-4\) from the 4th number in the sequence
\(2 + -4 = -2\)
option C
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Re: 1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with [#permalink] New post 25 Oct 2018, 04:38
Is there anoter solution
Re: 1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with   [#permalink] 25 Oct 2018, 04:38
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1, 2, -3, -4, 1, 2, -3, -4... The sequence above begins with

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