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# 0 > x > y > z > -1

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Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 [0], given: 220

0 > x > y > z > -1 [#permalink]  01 Oct 2017, 22:31
00:00

Question Stats:

40% (00:48) correct 60% (01:46) wrong based on 5 sessions
$$0 > x > y > z > -1$$

 Quantity A Quantity B x/y y/z

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 603 [2] , given: 124

Re: 0 > x > y > z > -1 [#permalink]  01 Oct 2017, 23:33
2
KUDOS
Bunuel wrote:
$$0 > x > y > z > -1$$

 Quantity A Quantity B x/y y/z

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.

Now lets consider two values

1st case let x=-0.1 , y =-0.2 . z =-0.3 (since we have to maintain the statement 0>x>y>z>-1)

Now QTY A = $$\frac{x}{y} = \frac{-0.1}{-0.2} = 0.5$$

QTY B = $$\frac{y}{z}= \frac{-0.2}{-0.3}= 0.6$$

Here QTY b >QTY a

Again if we consider

x=-0.2 , y =-0.4 . z =-0.9

Now QTY A = $$\frac{x}{y}= -\frac{0.2}{-0.4} = 0.5$$

QTY B = $$\frac{y}{z} =\frac{-0.4}{-0.9} = 0.4$$

So QTY a >QTY b.

Hence the option is D
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Re: 0 > x > y > z > -1   [#permalink] 01 Oct 2017, 23:33
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