Now lets consider two values

1st case let x=-0.1 , y =-0.2 . z =-0.3 (since we have to maintain the statement 0>x>y>z>-1)

Now QTY A = \(\frac{x}{y} = \frac{-0.1}{-0.2} = 0.5\)

QTY B = \(\frac{y}{z}= \frac{-0.2}{-0.3}= 0.6\)

Here QTY b >QTY a

Again if we consider

x=-0.2 , y =-0.4 . z =-0.9

Now QTY A = \(\frac{x}{y}= -\frac{0.2}{-0.4} = 0.5\)

QTY B = \(\frac{y}{z} =\frac{-0.4}{-0.9} = 0.4\)

So QTY a >QTY b.

Hence the option is D
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