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0 < b < c < d <e

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0 < b < c < d <e [#permalink] New post 02 Dec 2019, 03:10
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Question Stats:

33% (01:00) correct 66% (01:04) wrong based on 6 sessions
\(0 < b < c< d<e\)


List \(S: a,b,c,d,e\)

List \(T: a-2,b-1,c,,d+1,e+2\)


Quantity A
Quantity B
The standard deviation of the numbers in List \(S\)
The standard deviation of the numbers in List \(T\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: 0 < b < c< d<e [#permalink] New post 02 Dec 2019, 03:27
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Simple concept of standard deviation is tested here. which is how far the numbers are from the mean of the list.
Lets given some values, a=0, b=1, c=2, d=3, e=4 which is list S, that given list T as {-2,0,2,4,6}
A: the mean of list S is 2, the deviation from mean for respective numbers is {2,1,0,1,2}
B: the mean of list T is 2, the deviation from mean for respective numbers is {4,2,0,2,4}
Clearly, the numbers in list T are deviated more from the mean than numbers from list S, so the quantity A<B
Hence we choose option B as our answer.
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Re: 0 < b < c< d<e [#permalink] New post 02 Dec 2019, 07:00
I think the option should be D.
"a" can take on any value a>e (or a>>e) or a<b (a<<b)
We dont have any information on "a", one cant estimate changes in the standard estimation to go
e.g while we can prove B is greater, lets take values a,b,c,d,e = {1000,2,3,4,5}

For option B to be valid probably the question should be as: a<b<c<d<e ? (and not 0<b<c<d<e)
Re: 0 < b < c< d<e   [#permalink] 02 Dec 2019, 07:00
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