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0 < a < b < 1

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GMAT Club Legend
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4750
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1664 [0], given: 396

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0 < a < b < 1 [#permalink] New post 04 Mar 2018, 13:48
Expert's post
00:00

Question Stats:

89% (00:24) correct 10% (00:00) wrong based on 19 sessions
\(0 < a < b < 1\)

Quantity A
Quantity B
\(0\)
\(2(a-b)\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 1
Question: 7
Page: 494
[Reveal] Spoiler: OA

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Sandy
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4750
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1664 [0], given: 396

CAT Tests
Re: 0 < a < b < 1 [#permalink] New post 04 Mar 2018, 14:30
Expert's post
Explanation

You know that b is greater than a, so (a – b) will always be negative, and Quantity A will always be greater. Alternatively, you can solve this one by plugging in values for a and b.


Try making \(a= \frac{1}{4}\) and \(b=\frac{1}{2}\) : The value in Quantity B is now \(2(\frac{1}{4}-\frac{1}{2})=2\frac{-1}{4}=\frac{-1}{2}\).
Quantity A is greater, so eliminate choices (B) and (C).
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Sandy
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1 KUDOS received
GRE Instructor
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Joined: 10 Apr 2015
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Kudos [?]: 1140 [1] , given: 7

Re: 0 < a < b < 1 [#permalink] New post 05 Mar 2018, 09:19
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Expert's post
sandy wrote:
\(0 < a < b < 1\)

Quantity A
Quantity B
\(0\)
\(2(a-b)\)




We can solve this question using matching operations

Given:
Quantity A: 0
Quantity B: 2(a-b)

Expand Quantity B to get:
Quantity A: 0
Quantity B: 2a - 2b

Add 2b to both quantities to get:
Quantity A: 2b
Quantity B: 2a

Divide both quantities by 2 to get:
Quantity A: b
Quantity B: a

Since we're told that 0 < a < b < 1, we can see that Quantity A is greater.

Answer: A

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Intern
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Joined: 28 Feb 2018
Posts: 30
Followers: 0

Kudos [?]: 2 [0], given: 0

Re: 0 < a < b < 1 [#permalink] New post 11 Mar 2018, 07:12
B is a negative number So A is correct
Re: 0 < a < b < 1   [#permalink] 11 Mar 2018, 07:12
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