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# 0 > a > b

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Joined: 18 Apr 2015
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0 > a > b [#permalink]  22 Aug 2018, 09:10
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Question Stats:

67% (00:26) correct 32% (00:25) wrong based on 52 sessions
$$0 > a > b$$

 Quantity A Quantity B $$(ab)$$ $$(ab)^2$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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VP
Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Kudos [?]: 1309 [0], given: 251

Re: 0 > a > b [#permalink]  29 Aug 2018, 03:43
Carcass wrote:
$$0 > a > b$$

 Quantity A Quantity B $$(ab)$$ $$(ab)^2$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Since nothing is given for a and b,apart from -ve value, it can be integer value or fraction

$$0 > a > b$$

Let a = -1 and b = -2

Therefore QTYA = 2

QTY B = 4

QTY A < QTY B

Let take

a = $$-\frac{1}{2}$$, b= -1

QTY A =$$\frac{1}{2}$$

QTY B = $$\frac{1}{4}$$

So QTY A > QTY B

As we have two possibilities so the Option is D
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Re: 0 > a > b   [#permalink] 29 Aug 2018, 03:43
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