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# 0 < a < 1 < b < c

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0 < a < 1 < b < c [#permalink]  17 Oct 2017, 14:05
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Question Stats:

68% (00:34) correct 31% (00:25) wrong based on 16 sessions

$$0 < a < 1 < b < c$$

 Quantity A Quantity B $$\frac{c^2}{a}$$ $$\frac{bc}{ab}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: 0 < a < 1 < b < c [#permalink]  18 Oct 2017, 05:04
Quantity A has at the denominator a number lower than 1 but greater than zero, this means it increases when divided by it. Moreover, it has a numerator as the highest number among the three to the power of 2.

Quantity B, instead, has a number greater than 1 at the denominator and a lower numerator, given that b < c and thus bc < c^2.

This leads to the choice of B!

Putting in some numbers as a = 1/2, b = 2 and c = 3; we would get A = 3^2/(1/2) = 18 and B = 3*2/(1/2)*2 = 6.
Re: 0 < a < 1 < b < c   [#permalink] 18 Oct 2017, 05:04
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