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# The number of zeros at the end of m when written in integer

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The number of zeros at the end of m when written in integer [#permalink]  16 Sep 2017, 10:35
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m=2^{16}3^{17}4^{18}5^{19}

n=2^{19}3^{18}4^{17}5^{16}

 Quantity A Quantity B The number of zeros at the end of m whenwritten in integer form The number of zeros at the end of n whenwritten in integer form

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: The number of zeros at the end of m when written in integer [#permalink]  21 Sep 2017, 08:41
Any help with this one?
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Re: The number of zeros at the end of m when written in integer [#permalink]  05 Oct 2017, 18:01
1
KUDOS
can be written as
m = 2^16 3^17 4^17 5^16 4 5^3
n = 2^16 3^17 4^17 5^16 3 2^3
now we see in first 4 terms are same for both m and n but it m we see 5^3 * 4 that means two more zeroes
thats why quantity a is greater
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Re: The number of zeros at the end of m when written in integer [#permalink]  09 Oct 2017, 22:17
the number of zeroes will be determined by the number of 5s and 2s. since 5*2 gives us one zero, the number of zeroes will be the number of (5*2) that we get. So in first case it is 19 and in second case it is 16. Hence A is greater than B.
Re: The number of zeros at the end of m when written in integer   [#permalink] 09 Oct 2017, 22:17
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