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The following chart shows the employee breakdown, number of

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Manager
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Kudos [?]: 25 [0], given: 95

The following chart shows the employee breakdown, number of [#permalink] New post 11 Oct 2017, 22:08
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The following chart shows the employee breakdown, number of marketer vs. number of programmers, at six similarly sized companies in a particular internet market. All six have similar sized management teams that are not displayed: all the non-management employees are displayed.Image
1) At Pindar, there are approximately how many more programmers than marketers?

(A) 6

(B) 22

(C) 35

(D) 57

(E) 73

[Reveal] Spoiler: OA
B


2) At Jericho, approximately what percent of the non-management employees are marketers?

(A) 28%

(B) 42%

(C) 51%

(D) 66%

(E) 72%

[Reveal] Spoiler: OA
E


3) If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

(A) 6

(B) 13

(C) 20

(D) 26

(E) 33

[Reveal] Spoiler: OA
A




[Reveal] Spoiler:
Attachment:
Employee-Breakdowns-Six-Companies.jpg
Employee-Breakdowns-Six-Companies.jpg [ 27.69 KiB | Viewed 87 times ]



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Re: The following chart shows the employee breakdown, number of [#permalink] New post 15 Oct 2017, 01:11
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Q1: The number of marketers is around 35, while the number of programmers can be computed as 93-35 = 58. Then, there are 58-35 = 23 more marketers. Among the choice, the nearest is 22 (B)

Q2: The marketers are 67 out of 93, thus approximately 67/93*100 = 72%. (E)

Q3: The mean without Fermion is roughly 50.5, while including Fermion it becomes 45. Thus it decreases of approximately 6 points (A)
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The following chart shows the employee breakdown, number of

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