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# The diameter of the circle is 10

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The diameter of the circle is 10 [#permalink]  27 Dec 2016, 03:17
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The diameter of the circle is 10

 Quantity A Quantity B The area of the region enclosed by quadrilateral ABCD 40

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: The diameter of the circle is 10 [#permalink]  28 Dec 2016, 16:39
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Carcass wrote:

The diameter of the circle is 10

 Quantity A Quantity B The area of the region enclosed by quadrilateral ABCD 40

First of all, it's important not to read too much into the diagram.
All we can glean from the diagram is that we have a quadrilateral that is inscribed in the circle.
That's it!

So, first recognize that the inscribed quadrilateral COULD be a very very very narrow rectangle like this.

Notice that this quadrilateral COULD be so thin that its area is very very close to zero.
So, for this particular quadrilateral we get:
Quantity A: a very very small area that's close to zero
Quantity B: 40
In this case, Quantity B is greater.

Alternatively, we COULD make the quadrilateral quite large.
In fact, we could make it a SQUARE.

So, if the inscribed quadrilateral is a square, what is its area?
To find out, let's draw a diagonal.

One of our circle properties tells us that this diagonal must be the diameter of the circle, which we know is 10
To find the area of the square, we need to know the length of each side.
So, let's let x = the length of each side.

Since ACD is a RIGHT TRIANGLE, we can apply the Pythagorean Theorem to get: x² + x² = 10²
Simplify to get 2x² = 100
Divide both sides by 2 to get: x² = 50

This means the area of the square = 50
We know this because the area of the square = (x)(x) = x², and we just learned that x² = 50

So, for this particular quadrilateral we get:
Quantity A: 50
Quantity B: 40
In this case, Quantity A is greater.

Answer: D

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Re: The diameter of the circle is 10 [#permalink]  28 Jul 2017, 10:56
Could you please explain why we need to consider that the inscribe quadrilateral has a changing size. I mean that can be consider as a small rectangle or a big square.
Thanks so much.
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Re: The diameter of the circle is 10 [#permalink]  08 Aug 2017, 01:45
But, if we know that the diameter of the circle is 10, then the area of the circle is 25p, is not it? Therefore, we can assume that anything that is inscribed in the circle is going to be lower then 25p.
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Re: The diameter of the circle is 10 [#permalink]  28 Aug 2017, 11:51
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boxing506 wrote:
But, if we know that the diameter of the circle is 10, then the area of the circle is 25p, is not it? Therefore, we can assume that anything that is inscribed in the circle is going to be lower then 25p.

Be careful.
Area of circle = (pi)(radius²)
So, if the radius has length 5, then the area of the circle = (pi)(5²) = 25pi ≈ 75
So, if the area of the circle is approximately 75, then the area of the quadrilateral must be LESS THAN 75

Since quantity B is 40, this information (area of the quadrilateral must be LESS THAN 75) doesn't help much.
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Re: The diameter of the circle is 10   [#permalink] 28 Aug 2017, 11:51
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# The diameter of the circle is 10

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