It is currently 23 Oct 2017, 23:37
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

If |2z| – 1 ≥ 2, which of the following graphs could be a nu

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Moderator
Moderator
User avatar
Joined: 18 Apr 2015
Posts: 2164
Followers: 30

Kudos [?]: 314 [0], given: 1279

If |2z| – 1 ≥ 2, which of the following graphs could be a nu [#permalink] New post 21 Jun 2017, 13:17
Expert's post
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions


If |2z| – 1 ≥ 2, which of the following graphs could be a number line representing all the possible values of z?

Image
[Reveal] Spoiler: OA

_________________

Get the 17 FREE GREPrepclub Tests

1 KUDOS received
Senior Manager
Senior Manager
Joined: 03 Sep 2017
Posts: 409
Followers: 0

Kudos [?]: 124 [1] , given: 64

Re: If |2z| – 1 ≥ 2, which of the following graphs could be a nu [#permalink] New post 12 Oct 2017, 01:47
1
This post received
KUDOS
The equation is solved as

for x >= 0, 2z-1\geq 2 i.e. z\geq \frac{3}{2}

for x <= 0, -2z-1\geq 2 i.e. z\leq -\frac{3}{2}

Thus, the value of x are x\leq -\frac{3}{2} and x \geq \frac{3}{2}.

The line number is A because 3/2 is greater than 1 and -3/2 is less than -1
1 KUDOS received
Intern
Intern
Joined: 12 Oct 2017
Posts: 23
Followers: 0

Kudos [?]: 11 [1] , given: 3

Re: If |2z| – 1 ≥ 2, which of the following graphs could be a nu [#permalink] New post 12 Oct 2017, 09:19
1
This post received
KUDOS
Solutions :-

There Can be multiple ways to think over this problem but whenever we are finding answer from the given choices try to eliminate the wrong choice instead of finding the right one ( this is very useful in most of the cases )

In above problem, from the given choices we need to check the value for z=1 or -1 as for both |z| = 1

for z=1
equation is "1>=2"
which is not correct
so |z| should be greater than 1
or z should be greater than 1 or less than -1

if we check the choices, Choice "B,C,D,E" is eliminated as all are wrong so we are left with only Choice "A"

Answer :- "A"
1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 638
Followers: 29

Kudos [?]: 450 [1] , given: 3

Re: If |2z| – 1 ≥ 2, which of the following graphs could be a nu [#permalink] New post 12 Oct 2017, 15:17
1
This post received
KUDOS
Expert's post
Carcass wrote:


If |2z| – 1 ≥ 2, which of the following graphs could be a number line representing all the possible values of z?

Image


Another approach is to TEST SOME values.

When I scan the answer choices, I see that some have 0 as part of the solution, and others don't.
So, let's see what happens when z = 0

Plug z = 0 into original equation to get: |2(0)| – 1 ≥ 2
Evaluate to get: |0| – 1 ≥ 2
We get: 0 – 1 ≥ 2
And then: -1 ≥ 2
NOT TRUE.
So, z = 0 is NOT a solution.
Therefore, we'll ELIMINATE D and E, since they include z=0 as a solution.

Among the three remaining answer choices, two have have 1 as part of the solution, and one doesn't.
So, let's see what happens when z = 1
Plug z = 1 into original equation to get: |2(1)| – 1 ≥ 2
Evaluate to get: |2| – 1 ≥ 2
We get: 2 – 1 ≥ 2
And then: 1 ≥ 2
NOT TRUE.
So, z = 1 is NOT a solution.
Therefore, we'll ELIMINATE B and C, since they include z=1 as a solution.

By the process of elimination, we're left with A, the correct answer.

Cheers,
Brent
_________________

Brent Hanneson – Founder of greenlighttestprep.com

Image

Check out the online reviews of our course

Re: If |2z| – 1 ≥ 2, which of the following graphs could be a nu   [#permalink] 12 Oct 2017, 15:17
Display posts from previous: Sort by

If |2z| – 1 ≥ 2, which of the following graphs could be a nu

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GRE Prep Club Forum Home| About| Terms of Use| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.