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# A shopkeeper purchases birdfeeders for $10 each and s  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Moderator Joined: 18 Apr 2015 Posts: 2137 Followers: 30 Kudos [?]: 309 [0], given: 1265 A shopkeeper purchases birdfeeders for$10 each and s [#permalink]  27 Jul 2017, 09:59
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A shopkeeper purchases birdfeeders for $10 each and sells them for$18 each. If the cost of the feeders increases by 50% for two months in a row, what is the smallest percent increase the shopkeeper can apply to the selling price in order to avoid selling at a loss?

[Reveal] Spoiler:
25 %

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Re: A shopkeeper purchases birdfeeders for $10 each and s [#permalink] 25 Sep 2017, 06:15 If the cost increases by 50% for two consecutive months, it becomes (1+0.5)*(1+0.5)*20 = 22.5. Then, in order to avoid a loss, the selling cost must be equal to 22.5. Then, the percent increase in the selling cost should be [(22.5-18)/18]*100 = 25% Manager Joined: 20 Apr 2016 Posts: 208 Followers: 1 Kudos [?]: 120 [1] , given: 52 Re: A shopkeeper purchases birdfeeders for$10 each and s [#permalink]  25 Sep 2017, 07:59
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Carcass wrote:
A shopkeeper purchases birdfeeders for $10 each and sells them for$18 each. If the cost of the feeders increases by 50% for two months in a row, what is the smallest percent increase the shopkeeper can apply to the selling price in order to avoid selling at a loss?

[Reveal] Spoiler:
25 %

We have two times increase in birdfeed price:

for 1st $10 we have 10+50*\frac{10}{100} = 15 For 2nd price increase we have 15+15*\frac{50}{100} = 22.5 Now smallest % increase in Selling price should be = \frac{(22.5 -18)}{18} *100 = 25% _________________ If you found this post useful, please let me know by pressing the Kudos Button Re: A shopkeeper purchases birdfeeders for$10 each and s   [#permalink] 25 Sep 2017, 07:59
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